问题

我尝试将数据从表单发送到数据库.这是我使用的形式:

<form name="foo" action="form.php" method="POST" id="foo">
    <label for="bar">A bar</label>
    <input id="bar" name="bar" type="text" value="" />
    <input type="submit" value="Send" />
</form>

典型的方法是提交表单,但这会导致浏览器重定向.使用jQuery和 Ajax ,可以捕获所有表单的数据并提交它到PHP脚本(例如, form.php )?



解决方法

.ajax 的基本用法如下所示:

HTML:

<form id="foo">
    <label for="bar">A bar</label>
    <input id="bar" name="bar" type="text" value="" />

    <input type="submit" value="Send" />
</form>

JavaScript:

// Variable to hold request
var request;

// Bind to the submit event of our form
$("#foo").submit(function(event){

    // Prevent default posting of form - put here to work in case of errors
    event.preventDefault();

    // Abort any pending request
    if (request) {
        request.abort();
    }
    // setup some local variables
    var $form = $(this);

    // Let's select and cache all the fields
    var $inputs = $form.find("input, select, button, textarea");

    // Serialize the data in the form
    var serializedData = $form.serialize();

    // Let's disable the inputs for the duration of the Ajax request.
    // Note: we disable elements AFTER the form data has been serialized.
    // Disabled form elements will not be serialized.
    $inputs.prop("disabled", true);

    // Fire off the request to /form.php
    request = $.ajax({
        url: "/form.php",
        type: "post",
        data: serializedData
    });

    // Callback handler that will be called on success
    request.done(function (response, textStatus, jqXHR){
        // Log a message to the console
        console.log("Hooray, it worked!");
    });

    // Callback handler that will be called on failure
    request.fail(function (jqXHR, textStatus, errorThrown){
        // Log the error to the console
        console.error(
            "The following error occurred: "+
            textStatus, errorThrown
        );
    });

    // Callback handler that will be called regardless
    // if the request failed or succeeded
    request.always(function () {
        // Reenable the inputs
        $inputs.prop("disabled", false);
    });

});

注意:由于jQuery 1.8,.success,.error和.complete不推荐使用.done,.fail和.always.

注意:请记住,上述代码段必须在DOM准备就绪后才能完成,因此您应将其放在 $(document).ready() 处理程序(或使用 $()

提示:您可以链 a>这样的回调处理程序: $.ajax().done().fail().always();

PHP(也就是form.php):

// You can access the values posted by jQuery.ajax
// through the global variable $_POST, like this:
$bar = isset($_POST['bar']) ? $_POST['bar'] : null;

注意:始终清理发布的数据,防止注入和其他恶意代码.

您也可以使用 .post 的简写形式在上述JavaScript代码中的 .ajax :

$.post('/form.php', serializedData, function(response) {
    // Log the response to the console
    console.log("Response: "+response);
});

注意:上述JavaScript代码与jQuery 1.8及更高版本一起使用,但它应该与以前的版本一起使用到jQuery 1.5.




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